javascript之jQuery Ajax POST 请求

我正在尝试获取以下代码以通过 POST 将变量发送到 PHP 页面。我不太确定该怎么做。这是我的代码通过 GET 发送数据并通过 JSON 编码接收数据。我需要更改什么才能通过 POST 将变量传递到 process_parts.php？

function imagething(){ 
    var done = false, 
    offset = 0, 
    limit = 20; 
    if(!done) { 
        var url = "process_parts.php?offset=" + offset + "&limit=" + limit; 
 
        $.ajax({ 
            //async: false, defaults to async 
            url: url 
        }).done(function(response) { 
 
            if (response.processed !== limit) { 
                // asked to process 20, only processed <=19 - there aren't any more 
                done = true; 
            } 
            offset += response.processed; 
            $("#mybox").html("<span class=\"color_blue\">Processed a total of " + offset + " parts.</span>"); 
            alert(response.table_row); 
            console.log(response); 
            imagething(); //<--------------------------recursive call 
        }).fail(function(jqXHR, textStatus) { 
 
            $("#mybox").html("Error after processing " + offset + " parts. Error: " + textStatus); 
 
            done = true; 
        }); 
    } 
} 
imagething(); 

请您参考如下方法:

默认方法是GET，要更改它，请使用type 参数。您还可以将查询字符串属性作为对象提供，以便它们在 URL 中不会立即明显:

var url = "process_parts.php"; 
 
$.ajax({ 
    url: url, 
    type: 'POST', 
    data: { 
        offset: offset, 
        limit: limit 
    }  
}).done(function() { 
    // rest of your code... 
});